Method for drawing an antiprism with equilateral sides
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Hey what happened to all those steps you wrote out Tig?
Anyway I guess the circle approximation is the best we can do...
Thanks everyone
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Here's an improved version of the Steps
It works for any size 'cube'... -
TIG - This Is Google
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Much easier
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Thanks Tig. You're a genius.
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woops!
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@sketchup_roolz said:
Not that anyone cares anymore but here's a my proper 2D method...
http://img573.imageshack.us/img573/272/68861221.pngI fixed your faulty link...
An interesting alternative approach...
I am thinking how it might get converted to an 'algorithm'...
Which must be possible as it involves 45/30/15 degree triangles with known side length...
Sleeping on it now... -
Not that anyone cares anymore but here's a my proper 2D method...
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Very clever Jeff.
Much appreciation for all the hard work here.
I don't really have a practical need to get this level of precision/accuracy but problems like this totally consume me.
I figured the faster I could figure it out it the sooner I could move on to more important things! (or not)SketchUp is an amazing piece of software and maybe one day I'll have a more concrete use for it.
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Why anybody save the SKP file "save as SU6"?
Like this anybody can reload easily any file! -
PS :How many triangles must have the polyedra?
On the first post there are 8 on "the plan"
On the Xray Tig volume there are 7 !
@unknownuser said:
Won't the file lose some of its v7, and v8 features. Did v6 have "dynamic components", etc.?
there are rarelly dynamic component in "hard geometry" like in this post or exotic functions
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@unknownuser said:
Why anybody save the SKP file "save as SU6"?
Like this anybody can reload easily any file!
Won't the file lose some of its v7, and v8 features. Did v6 have "dynamic components", etc.?
Btw, am I sticking my foot in my mouth? I didn't read all of the posts.
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@unknownuser said:
Why anybody save the SKP file "save as SU6"?
Like this anybody can reload easily any file!oops, i try to remember to do this prior to uploading at scf but i just forget sometimes
i added a v6 file to my earlier post -
???????????
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???????????
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here's another solution that allows rotating without the mega-segment arc..
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@unknownuser said:
PS :How many triangles must have the polyedra?
On the first post there are 8 on "the plan"
On the Xray Tig volume there are 7 !i don't think it matters.. here's an example using octagons with one of them rotated 22.5 degrees then using the same exact method i used for the squares.. resulting in 16 equal sides. (i think the people trying it though are using the wiki example which has 7 sides.)
edit -- lol. the wiki one, the one i drew, the one tig drew..etc have 8 sides hah
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@unknownuser said:
PS :How many triangles must have the polyhedron?
On the first post there are 8 on "the plan"
On the Xray TIG volume there are 7 !@unknownuser said:
Won't the file lose some of its v7, and v8 features. Did v6 have "dynamic components", etc.?
there are rarely dynamic component in "hard geometry" like in this post or exotic functions
In my Xray volume there are 8 triangles BUT the left-hand-most one is almost square to the camera
A very neat solution by Jeff BTW... -
If you think about it... as you increase the number of sides for the top and bottom faces the nearer they approximate the circles and the smaller the sides of the equilateral triangles forming the side facets so the 'height' decreases until with thousands of sides the top and bottom are approaching coplanarity...
The simplest form has equilateral triangular faces, the next squares and so on.
there are always twice as many sides as the edges to the faces: so the triangle solution has 3x2=6 sides, the square 4x2=8 sides and so on... -
Ahhhh! I was victim of the perspective's law
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