Once upon a time... A Puzzle

remus

Well done jeff I was starting to think no one would get it.

jeff hammond

so no takers on this one?

1
11
21
1211
111221
312211
13112221
1113213211

i'll give it another day or so before revealing..

no more puzzles? i'm addicted to things like this..

remus

31131211131221?

jeff hammond

bingo! nice work remus

the puzzle is called a look-say.. basically, look at the line then say/write what you see..

1 = one one.. there is one one so the next line is 11
11= two ones.. there are two ones so the next line is 21
etc..

pilou

@unknownuser said:

so no takers on this one?

Seems I have given the solution in my previous post?
Reread it carrefully And the task to keep fresh research for others

SCQTDU next one? (little hint in my name in my signature)

jeff hammond

@unknownuser said:

@unknownuser said:

so no takers on this one?

Seems I have given the solution in my previous post?

oh man, you're right..

1n1e1x1t1space1l1i1n1e1

i fully missed what you were saying there

jeff hammond

@unknownuser said:

SCQTDU next one? (little hint in my name in my signature)

i barely know any french but it appears to work in spanish as well.. uno,dos,tres,quatro,cinco,seis..

my guess for the next letter would then be 'C' for cero.. if C is wrong then my guess is:

whatever the first letter is in the translation of 'zero' in french..

TIG

zero is zero...

jeff hammond

@tig said:

zero is zero...

haha..
ok, then my guess is 'Z'

pilou

remus

Try this:

1,1,2,3,5,8,13...

Whats the next number?

pilou

seems 21 but in this sort of successions there are often several arguing possibilities

TIG

@unknownuser said:

Try this:

1,1,2,3,5,8,13...

What's the next number?

Fibonacci ...21,34,55,89,144,233,377,610,987,1597,2584,4181,6765... etc
http://en.wikipedia.org/wiki/Fibonacci_number

pilou

Yes but this one will also valuable
1 1 2 3 5 8 13 13 14 15 20 25 25 etc...sure totally arbitrary but apply with an interval repetition

jeff hammond

Outside a room there are three light switches. Each switch is connected to a different light bulb inside the room.
Each of the three switches can be either 'ON' or 'OFF'.
You are allowed to set each switch the way you want it and then enter the room. you can only do this once.

Your task is to then determine which switch controls which bulb. How can you do it?

Ecuadorian

I ask someone to stay outside the room and help me.
I tie a string to one of the switches, then enter the room.
I call the architect and tell him how bad his design is for having put the switches outside.
I give up.

jeff hammond

@ecuadorian said:

I ask someone to stay outside the room and help me.

I tie a string to one of the switches, then enter the room.

I call the architect and tell him how bad his design is for having put the switches outside.

I give up.

haha #3 sounds good.
1 & 2 are not allowed. (or anything like those)
4 - nah - there's a real solution

oh, and i should add.. if you fail, something terrible will happen.. let's say nuclear war

remus

Is there a sneaky trick to it, or is there a combination of on/offs that you can set to work it out?

Ecuadorian

Ok, I cheated and found the answer online. I can give a hint: The thing you can only do once is enter the room.

And I'll give you a puzzle I've just made up. This one is for the Japanese speakers and Japanese language learners in the forum:
3txq
What is the next character in the sequence?

jeff hammond

no Remus. Nothing sneaky.

[edit] well, maybe.. there isn't a sole combination of on/off's that will tell you the answer.. there's something else to it but that something else is logic based.. not something you're going to be mad about when you realize the solution..

and yeah, you can only enter the room once.. you can do whatever you want prior to going in.