Lengths over trigonometric

[hermannausowl]

How can I determine the lengths over trigonometric functions by program?
[img][attachment=0:3et1o13z]<!--%20ia0%20-->Dachschraege-Szene%2001.jpg<!--%20ia0%20-->[/attachment:3et1o13z][/img]

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[pilou]

EDIT: SORRY I DON'T SEEN THAT I WAS IN THE DEVELOPER SECTION!

The tape measure tool and protractor are not sufficient ?
For the "top"
You have vertical thickness given, angle wished given
Juast draw it! At the intersection you will have your lenght

Due the precision of SKetchup

If you want make real easy geometry try MOI 3D

There is an infinite demo without save but enough sufficient! (see my images above)
Just make a snapshot of the screen (Key Print Screen and past it on your favorite 2D Prog!
You have even a script for save the screen at any size

Replace the x,y 2560 and 2560 by any that you want but carreful it's following your hard memory! (so make some trying

script:var v = moi.ui.getActiveViewport(); if ( v != null ) { moi.view.lineWidth = 4; v.renderToClipboard( 2560, 2560 ); moi.view.lineWidth = 1; }

for a Tickness of 1 and angle of 29.75° I have 1.7496371 (In Moi)
1.749637 in Sketchup Same result in this case because no circles involved and angles very smart!

[TIG]

This is pretty basic 'trigonometry'...
[Should have listened more carefully in class ]

The ' opposite_side' of a right-angled triangle is found by adjacent_side * Math::tan(angle)

The 'angle' needs to be in radians, so if you have it in degrees then you need to use angle.degrees

There are similar equations for finding the other sides depending on the known angles/sides etc...

There are many Internet sites giving advice...