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    Using laser distance meters in bright sun

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    • GaieusG Offline
      Gaieus
      last edited by

      I also have a Bosch meter and it has a function to measure the shortest or longest route you are "sweeping through". Here are two, quick sketches what it does:

      Min.png
      Max.png
      These methods are very handy when I cannot see the small, red dot of the laser scanner (which can indeed happen especially during light daytime on sunny surfaces).

      I also have a stick of 1.5 metres long which I use to put my scanner on top when measuring the heights of buildings. This way I do not need to lean down to measure from the ground or measure twice (once up and once down from eye/measure height) to add the two values. Basically I start from a footprint, PP it up to 150 cms - then make the measurements and only add what I measure then.

      Gai...

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      • mitcorbM Offline
        mitcorb
        last edited by

        Hi, Roger:
        I fully appreciate your reply to my reply, especially on the economics. And I was aware that the Scanstation would represent a "significant capital outlay", to use a bland euphemistic phrase.

        @Gaieus: That method is enlightening. Similarly Leica lets you do a Pythagorean process to arrive at building heights, or other distances. And, as you pointed out, without an established steady station point (top end of stick) the data can be worthless.

        I take the slow, deliberate approach in my aimless wandering.

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        • B Offline
          bjornkn
          last edited by

          So what if the walls are not perfectly straight?
          Lots of buildings have tapering walls, like Inca buildings, fortresses etc, and many have walls skewed by time/age and bad foundations, like the tower in Pisa etc.
          Pythagoras won't help much then, will it?
          I'm sure the Leica Disto D8 is a very useful tool, that can also do some angle measurements afaik, but will it be enough power/precision for such situations?
          And with a price tag a lot higher (at least in this country ~US$1400) than the tgi3D/PhotoScan I know what I would have chosen ๐Ÿ˜‰ But a cheap Bosch laser would probably be quite useful for measuring a reference distance. So far I have gotten enough precision with a 5m tape measure.

          A bit OT:
          A little while ago I saw a TV program from a volcanic rift (?) in Ethopia(?) where the team wanted to make a 3D scan of the extremely hot rift which puffed out toxic gases all the time. They rigged the laser scanner on a steel cable crossing the rift, and lowered it down to make the scan. They had to give up after a while, but they did get some parts of it 3D scanned. I can't help but smiling a little at their efforts, when they could have used the KISS principle and easily/safely gotten good results using PhotoScan (or similar software like PhotoModeler)

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          • GaieusG Offline
            Gaieus
            last edited by

            @mitcorb said:

            Similarly Leica lets you do a Pythagorean process to arrive at building heights, or other distances.

            Yeah, I wished I could get one of those but mine does not do Pythagoras. Of course, I can do it if I really need to ๐Ÿ˜„

            @bjornkn said:

            Lots of buildings have tapering walls, like Inca buildings, fortresses etc, and many have walls skewed by time/age and bad foundations, like the tower in Pisa etc.

            That's true however the majority of buildings are (fortunately) rectangular/vertical (more or less). If not, we get out our secondary school geometry books again and do some calculations. ๐Ÿ˜„

            Gai...

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            • B Offline
              bjornkn
              last edited by

              @gaieus said:

              That's true however the majority of buildings are (fortunately) rectangular/vertical (more or less). If not, we get out our secondary school geometry books again and do some calculations. ๐Ÿ˜„
              Wonder how those formulas look? ๐Ÿ˜‰

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              • GaieusG Offline
                Gaieus
                last edited by

                The book are in the attic ATM. I should get them down one day...
                ๐Ÿ˜„

                Gai...

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                • R Offline
                  Roger
                  last edited by

                  SOH-CAH-TOA:

                  Sine = Opposite รท Hypotenuse
                  Cosine = Adjacent รท Hypotenuse
                  Tangent = Opposite รท Adjacent 
                  

                  or

                  Some Old Hippy Caught Another Hippy Trippin' On Acid

                  http://www.azcreative.com

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                  • R Offline
                    Roger
                    last edited by

                    @gaieus said:

                    I also have a Bosch meter and it has a function to measure the shortest or longest route you are "sweeping through". Here are two, quick sketches what it does:

                    DOH! Thanks, I don't remember seeing this in the instruction sheet. But then the whole thing looked so simple that I tossed the instruction without reading. Thanks Gaieus.

                    http://www.azcreative.com

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                    • GaieusG Offline
                      Gaieus
                      last edited by

                      Well, devices of even the same brand can be very different so there may not be this function on yours. Yet of course looking it up would be best.

                      Gai...

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                      • B Offline
                        bjornkn
                        last edited by

                        @Roger :
                        Afaik sin/cos/tan only works on right-angled triangles, and so do the Pythagoras rule a^2+b^2=c^2 - or here : a=sqr(c^2-b^2)
                        That's why I was so interested in the formulas in Gaieus' books. Too bad they are in the attic ๐Ÿ˜‰

                        BTW, did you get that iPhone theodolite to work with any precision?

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                        • R Offline
                          Roger
                          last edited by

                          Bjorn, any triangle can be divided into two right triangles, each of which can be solved by pythagoras or sohcahtoa.

                          http://www.azcreative.com

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                          • B Offline
                            bjornkn
                            last edited by

                            @roger said:

                            Bjorn, any triangle can be divided into two right triangles, each of which can be solved by pythagoras or sohcahtoa.

                            Yes, as long as you know some angles?
                            Or if you measure from 2 positions?

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                            • TIGT Offline
                              TIG Moderator
                              last edited by

                              While we are on 'formulas'...

                              If you know two sides of any triangle and the angle between them then you can find the length of the other side opposite that angle using the Cosine Rule
                              a^2 = b^2 + c^2 - 2bc*cosA
                              can be rearranged to give the side a thus...
                              a = sqrt(b^2 + c^2 - 2bc*cosA)
                              Notes:
                              Side 'a' is opposite angle 'A'.
                              There are obviously the other two versions of the equation for the two other sides, but you can give them the reference you want so you always find 'a' without needing to have these in memory!

                              The Sine Rule works for any two angles and one related side, from which you can find the another side
                              a / sinA = b / sinB = c / sinC = D
                              which can be rearranged to give the side a thus...
                              a = b * sinA / sinB
                              Notes:
                              Side 'a' is opposite angle 'A' and so on.
                              The ratios are all equal to D, which is the diameter of the circle that passes through all of the three vertices of the triangle - the radius of that circle is D/2.
                              To find the area of any triangle where you know two sides and the angle between them use
                              Area = a * b * sinC / 2

                              ๐Ÿค“

                              TIG

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                              • R Offline
                                Roger
                                last edited by

                                Folding stick
                                My folding meter stick with distance measure on top

                                Long stick
                                Stick unfolded - the distance (outer edge to outer edge) of the two yellow reflective tapes is 3ft.

                                Target bar
                                Laser target bar hung magnetically on wall corner. Reflective tape is 1 ft long and entire black bar is 22 inches.

                                Neodymium magnets
                                This is the back of the target bar. The circles are neodymium super magnets affixed with double sided tape. There are also holes in the bar that can be used with push pins, nails, strings, picture hooks, and clamps.

                                Stick with compass
                                This is the stick with compass

                                Distance meter mounted on stick
                                Compass remove and distance meter in place.

                                http://www.azcreative.com

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                                • B Offline
                                  bjornkn
                                  last edited by

                                  @tig said:

                                  While we are on 'formulas'...

                                  If you know two sides of any triangle and the angle between them then you can find the length of the other side opposite that angle using the Cosine Rule

                                  Exactly!
                                  But you need to know one angle (which may be 90 degrees) and 2 sides to calculate the length of the third, right?
                                  With only 2 sides and no angle you can't know the length of the third side?
                                  But if the wall is vertical (90 degrees) you can calculate without using sin/cos, but just the a^2+b^2=c^2?

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                                  • B Offline
                                    bjornkn
                                    last edited by

                                    Is there a built-in level in the Bosch laser then?

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                                    • R Offline
                                      Roger
                                      last edited by

                                      @bjornkn said:

                                      Is there a built-in level in the Bosch laser then?

                                      I am designing and building an accessory to attach a level and a small monocular and the whole device will clip to my meter/yard/walking stick.

                                      http://www.azcreative.com

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                                      • R Offline
                                        Roger
                                        last edited by

                                        @bjornkn said:

                                        @roger said:

                                        Bjorn, any triangle can be divided into two right triangles, each of which can be solved by pythagoras or sohcahtoa.

                                        Yes, as long as you know some angles?
                                        Or if you measure from 2 positions?

                                        Two angles with the enclosed side or two sides and the enclosed angle. And if you know one angle to begin with and divide the triangle into two right triangles you will know your first angle, your second angle will be the right triangle (90 degrees). Then if you add known angle to 90 degrees and subtract the result from 180 degrees you know the third angle.

                                        http://www.azcreative.com

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                                        • R Offline
                                          Roger
                                          last edited by

                                          @bjornkn said:

                                          Is there a built-in level in the Bosch laser then?

                                          You did not fully understand the point of Gaieus' diagram and comments. As you sweep the meter up and down the distance reading will change. It starts out long reaches its shortest point and then gets long again. The angle where the distance is shortest is a perpendicular to the wall. When the distance is the shortest, you have a 90 degree angle between the wall and the laser line.

                                          http://www.azcreative.com

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                                          • TIGT Offline
                                            TIG Moderator
                                            last edited by

                                            Also don't forget the 'Similar Triangle' method to get the height of something too tall to measure directly - this uses 'bright-sunlight' because it has to have a shadow - no gadgets required!Capture.PNG

                                            TIG

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